Question

How do you five the vertex and axis of symmetry `f(x) = 1/3(x + 5)^2 - 1`?

Answer 1

`(-5,-1)" and "x=-5`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))`

`"where "(h,k)" are the coordinates of the vertex and a"`
`"is a multiplier"`

`f(x)=1/3(x+5)^2-1" is in vertex form"`

`"with "h=-5" and "k=-1`

`rArrcolor(magenta)"vertex "=(-5,-1)`

`"the axis of symmetry passes through the vertex is"`
`"vertical and has equation"`

`x=-5`
graph{(y-1/3x^2-10/3x-22/3)(y-1000x-5000)=0 [-10, 10, -5, 5]}