How do you graph #3x+2y=8#?

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Answer 1 · 2018-03-04T22:47:52

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(3 * 0) + 2y = 8#

#0 + 2y = 8#

#2y = 8#

#(2y)/color(red)(2) = 8/color(red)(2)#

#y = 4# or #(0, 4)#

Second Point: For #x = 2#

#(3 * 2) + 2y = 8#

#6 + 2y = 8#

#6 - color(red)(6) + 2y = 8 - color(red)(6)#

#0 + 2y = 2#

#2y = 2#

#(2y)/color(red)(2) = 2/color(red)(2)#

#y = 1# or #(2, 1)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.025)((x-2)^2+(y-1)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x+2y-8)(x^2+(y-4)^2-0.025)((x-2)^2+(y-1)^2-0.025)=0 [-10, 10, -5, 5]}