How do you graph #3y+4x=12#?
1 Answer
Feb 15, 2017
This is a straight line through
Explanation:
Notice that the terms are linear or constant, so this equation represents a straight line.
We can find the intersections with the
So putting
#3y = 12#
Dividing both sides by
#y=4#
So the line intercepts the
If we instead put
#4x=12#
and hence:
#x=3#
So the
We can now draw our line through these two intercepts:
graph{(4x+3y-12)((x-3)^2+y^2-0.01)(x^2+(y-4)^2-0.01) = 0 [-9.21, 10.79, -2.28, 7.72]}