How do you graph #f(x)=sqrt(x-3)+4#?

1 Answer
Feb 3, 2015

First of all I have to be careful with the square root. I do not want a negative argument, so I set:
#(x-3)>=0# and so:
#x>=3#
This means that I can only give values of #x# starting from #3# and going up (I cannot give #2#, #1#, #0# etc..)

Then I'll choose "friendly" values of #x# in the sense that using them I can easily evaluate the square root:

For example:
#x=3# #-># #y=0+4=4#
#x=4# #-># #y=1+4=5#
#x=7# #-># #y=2+4=6#
#x=12# #-># #y=3+4=7#
...etc

I can now plot my graph:
enter image source here