How do you graph #y = \sqrt{4x+4}#?

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Answer 1 · 2014-11-12T02:34:30

By rewriting a bit,

#y=sqrt{4x+4}=sqrt{4(x+1)}=sqrt{4}sqrt{x+1}=2sqrt{x+1}#

Step 1: Sketching the graph of #y=sqrt{x}#.

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Step 2: Sketch the graph of #y=2sqrt{x}# by vertically stretching the graph in Step 1 by a factor of #2#.

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Step 3: Sketch the graph of #y=2sqrt{x+1}# by shifting the graph in Step 2 to the left by 1 unit.

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I hope that this was helpful.