How do you graph $r = 4cos(5θ)$ ?

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Answer 1 · 2018-03-07T15:38:40

As below

Standard form of equation is $y = a cos bx + c) + d$

$y = 4 cos (5theta)$

Amplitude $= a = 4$

Period $= (2pi) / |b| = (2pi) / 5$

Phase shift $= c / b = 0$ , $color(white)(aaaaa)(0$ shift to the right)

Vertical shift $= d = 0$

graph{4 cos (5x) [-10, 10, -5, 5]}

How do you graph r = 4cos(5θ)r = 4cos(5θ)?