How do you graph $r=-6sintheta$ ?

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Answer 1 · 2016-10-01T01:29:20

It is a circle with center at (0, -3) and radius, 3:
$x^2 + (y - -3)^2 = 3^2$

Multiply both sides by r:

$r^2 = -6rsin(theta)$

Substitute $x^2 + y^2$ for r and y for $rsin(theta)$

$x^2 + y^2 = -6y$

$x^2 + y^2 + 6y = 0$

$x^2 + y^2 + 6y + 9 = 9$

$x^2 + (y + 3)^2 = 3^2$

$x^2 + (y - -3)^2 = 3^2$

How do you graph r=-6sinthetar=-6sintheta?