Question

How do you graph the equation by plotting points `y = 1/(1 + x^2)`?

Answer 1

You make a list of `x`-values and the corresponding `y`-values.

Explanation:

The points will be all `(x,y)` combinations you calculated.
Notice that `x` is only in `x^2` form, so the negative values of `x` will give the same result as the positive. In other words, the graph is symmetrical with `x=0` as axis of symmetry.
Maximum will be at `(0,1)` and `y=0` is the horizontal asymptote
graph{1/(1+x^2) [-4.382, 4.386, -2.19, 2.192]}