How do you graph the point $M (2, - 90^{o})$ $M(2,-90^o)$ ?

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Answer 1 · 2016-12-02T17:50:25

see below

From the polar axis (positive x-axis) go down $90^{\circ}$ $90^@$ . You will end up on the ray $270^{\circ}$ $270^@$ .

Then plot the point at the intersection of the 2nd circle and the ray $270^{\circ}$ $270^@$ .

How do you graph the point M(2,-90^o)M(2,−90o)M(2,-90^o)?