Question

How do you graph the point `P(-0.5, -(11pi)/6)`?

Answer 1

Plot point `(-\sqrt3/4, 1/4)`

Explanation:

The Cartesian coordinates `(x, y)` of the point `(r, \theta)\equiv(-0.5, -{11\pi}/6)` are given as follows

`x=r\cos\theta=(-0.5)\cos(-{11\pi}/6)=-\sqrt3/4`

`y=r\cos\theta=(-0.5)\sin(-{11\pi}/6)=1/4`

Now, plot the point `(-\sqrt3/4, 1/4)` on XY plane