How do you graph #y-2x=5#?
1 Answer
Mar 4, 2018
See a solution process below:
Explanation:
First, solve for two points which solve the equation and plot these points:
First Point: For
Second Point: For
We can next plot the two points on the coordinate plane:
graph{(x^2+(y-5)^2-0.08)((x-1)^2+(y-7)^2-0.08)=0 [-20, 20, -10, 10]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y-2x-5)(x^2+(y-5)^2-0.08)((x-1)^2+(y-7)^2-0.08)=0 [-20, 20, -10, 10]}