How do you graph #y=x/(x^2-9)# using asymptotes, intercepts, end behavior?
1 Answer
Nov 11, 2016
The vertical asymptotes are
The horizontal asymptote is
No slant asymptotes
Only one intercept at
Explanation:
Let's factorise the denominator
As we canot divide by
As the degree of the numerator is
So,
The intercept is, when
graph{x/(x^2-9) [-11.25, 11.24, -5.63, 5.62]}