Question

How do you integrate `36/(2x+1)^3`?

Answer 1

`-9/(2x + 1)^2 + C`

Explanation:

`u = 2x + 1 Rightarrow du = 2 cdot dx`

`int 36/u^3 cdot {du}/2 = 18 int u^{-3} cdot du`

`= 18 u^{-2}/{-2} + C = -9/u^2 + C`