Question

How do you integrate `(x-2)/(x-1)`?

Answer 1

`(x-2)/(x-1) = (x-1-1)/(x-1) = (x-1)/(x-1)-1/(x-1) = 1-1/(x-1)`

Explanation:

`int(x-2)/(x-1) dx = int(1-1/(x-1)) dx`

`= x-ln abs(x-1) +C`