How do you multiply #(-3+2i)(-3-4i)#?

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Answer 1 · 2017-09-14T16:34:33

Just like any other polynomials....

...except any time you get a multiple of #i^2#, remove the #i# and change the sign on the coefficient.

(-3 + 2i)(-3 - 4i) =

#(-3 * -3) + (-3 * -4i) + (2i * -3) + (2i * 4i)#

#= 9 + 12i - 6i + 8i^2#

#= 9 + 6i -8#

#= 1 + 6i#

GOOD LUCK!