How do you multiply $(- 3 - 7 i) (- 12 - 2 i)$ $(-3-7i)(-12-2i)$ ?

Question

How do you multiply $(- 3 - 7 i) (- 12 - 2 i)$ $(-3-7i)(-12-2i)$ ?

1 Answer

Impact of this question

1669 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-12T20:40:49

$22 + 90 i$ $22+90i$

Explanation:

$note i^{2} = {(\sqrt{- 1})}^{2} = - 1$ $"note "i^2=(sqrt(-1))^2=-1$

$expand using FOIL and collect like terms$ $"expand using FOIL and collect like terms"$

$\Rightarrow (- 3 - 7 i) (- 12 - 2 i)$ $rArr(-3-7i)(-12-2i)$

$= 36 + 6 i + 84 i + 14 i^{2}$ $=36+6i+84i+14i^2$

$= 36 + 90 i - 14$ $=36+90i-14$

$= 22 + 90 i \leftarrow in standard form$ $=22+90ilarrcolor(red)"in standard form"$

Science

Math

Humanities

... and beyond

How do you multiply $(- 3 - 7 i) (- 12 - 2 i)$ $(-3-7i)(-12-2i)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you multiply (−3−7i)(−12−2i)(-3-7i)(-12-2i)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you multiply $(- 3 - 7 i) (- 12 - 2 i)$ $(-3-7i)(-12-2i)$ ?