How do you multiply #(-3j^7k^5)(-8jk^8)#?

Question

↳Redirected from "What is the chemical formula of a carbohydrate?"

2577 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-10T08:45:26

#(-3j^7k^5)(-8jk^8)#

# = (-3*-8)*(j^7*j)*(k^5*k^8)#

# = 24*(j^7*j)*(k^5*k^8)#

In general, #color(blue)(a^m*a^n = a^(m+n)#

# = 24*(j^(7+1))*(k^(5+8))#

#color(green)( = 24*j^8*k^13#