How do you multiply #3x(5x^2-x+4)#? Algebra Polynomials and Factoring Multiplication of Monomials by Polynomials 1 Answer Jacobi J. · Tony B May 25, 2018 #15x^3-3x^2+12x# Explanation: We need to distribute the #3x# to all terms in the parenthesis. We essentially have #color(blue)(3x)(5x^2)-color(blue)(3x)(x)+color(blue)(3x)(4)# Notice, the #3x# is being multiplied by all terms. We get #bar(ul(|color(white)(2/2)15x^3-3x^2+12xcolor(white)(2/2)|))# as our final answer. Hope this helps! Answer link Related questions What is Multiplication of Monomials by Polynomials? How do you multiply monomials by polynomials? How do you multiply monomials by monomials? How do you multiply #(3xy^5)(-6x^4y^2)#? How do you multiply and simplify #6ab(-10a^2 b^3+c^5)#? How do you simplify #-3a^2b(9a^2-4b^2)#? How do you multiply #y(xy^4)#? How do you multiply #(2x-1)(x^3-2x^2+3x-4)#? How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#? How do you simplify #2t^2+(3+5)(4t)#? See all questions in Multiplication of Monomials by Polynomials Impact of this question 1949 views around the world You can reuse this answer Creative Commons License