Question

How do you multiply `(4-2i) (3 + 2i)`?

Answer 1

`16 +2 i`

Explanation:

`(4-2 i)(3+2 i) = 12 + 8 i - 6 i - 4 i^2`

`=12 + 2 i - 4 * (-1) ; [i^2 = -1]`

`=12 + 2 i +4 = 16 +2 i` [Ans]