How do you multiply #(-5-i)(-2+2i)#?
1 Answer
Feb 2, 2016
12 - 8i
Explanation:
distribute the brackets in the usual way using FOIL.
Remember that
# i^2 = (sqrt-1)^2 = -1 #
#(-5 - i )(-2+2i ) = 10 - 10i + 2i - 2i^2 #
# = 10 - 8i + 2 = 12 - 8i #
