How do you multiply $6 x^{2} (- 2 x^{2} + 5 x - 30)$ $6x^2(-2x^2+5x-30)$ ?

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How do you multiply $6 x^{2} (- 2 x^{2} + 5 x - 30)$ $6x^2(-2x^2+5x-30)$ ?

2 Answers

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Answer 1 · 2017-07-03T15:59:24

See a solution process below:

Explanation:

Multiply each term within the parenthesis by the term outside the parenthesis:

$6 x^{2} (- 2 x^{2} + 5 x - 30) \Rightarrow$ $color(red)(6x^2)(-2x^2 + 5x - 30) =>$

$(6 x^{2} \times - 2 x^{2}) + (6 x^{2} \times 5 x) - (6 x^{2} \times 30)$ $(color(red)(6x^2) xx -2x^2) + (color(red)(6x^2) xx 5x) - (color(red)(6x^2) xx 30)$

Use this rule of exponents to multiply the variables in the individual terms:

$x^{a} \times x^{b} = x^{a + b}$ $x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))$

$- 12 x^{4} + 30 x^{3} - 180 x^{2}$ $-12x^4 + 30x^3 - 180x^2$

Answer 2 · 2017-07-03T16:00:27

You distribute the $6 x^{2}$ $6x^2$ throughout the polynomial.

Explanation:

$6 x^{2} \cdot (- 2 x^{2}) = - 12 x^{4}$ $6x^2 * (-2x^2) = -12x^4$

$6 x^{2} \cdot 5 x = 30 x^{3}$ $6x^2 * 5x = 30x^3$

$6 x^{2} \cdot (- 30) = - 180 x^{2}$ $6x^2 * (-30) = -180x^2$

So, your answer is

$- 12 x^{4} + 30 x^{3} - 180 x^{2}$ $-12x^4 + 30x^3 - 180x^2$

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How do you multiply $6 x^{2} (- 2 x^{2} + 5 x - 30)$ $6x^2(-2x^2+5x-30)$ ?

2 Answers

Explanation:

Explanation:

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How do you multiply $6 x^{2} (- 2 x^{2} + 5 x - 30)$ $6x^2(-2x^2+5x-30)$ ?