How do you multiply $7 c (5 - y + 4 y^{2})$ $7c(5-y+4y^2)$ ?

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Answer 1 · 2017-02-14T13:27:20

See the entire solution process below:

To multiply this expression you need to multiply every term in the parenthesis by $7 c$ $color(red)(7c)$

$7 c (5 - y + 4 y^{2}$ $color(red)(7c)(5 - y + 4y^2$ becomes:

$(7 c \times 5) - (7 c \times y) + (7 c \times 4 y^{2}) \to$ $(color(red)(7c) xx 5) - (color(red)(7c) xx y) + (color(red)(7c) xx 4y^2) ->$

$35 c - 7 c y + 28 c y^{2}$ $35c - 7cy + 28cy^2$

Or, writing it in standard form:

$28 c y^{2} - 7 c y + 35 c$ $28cy^2 - 7cy + 35c$

How do you multiply 7c(5-y+4y^2)7c(5−y+4y2)7c(5-y+4y^2)?