How do you multiply $- x (4 x^{2} - 2 x) - 5 x^{3}$ $-x (4x^2 - 2x) - 5x^3$ ?

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Answer 1 · 2018-03-20T03:20:15

$- x (4 x^{2} - 2 x) - 5 x^{3} = - 9 x^{3} + 2 x^{2}$ $-x (4x^2 - 2x) - 5x^3 = color(brown)(-9x^3 + 2x^2$

$- x (4 x^{2} - 2 x) - 5 x^{3}$ $-x (4x^2 - 2x) - 5x^3$

$\Rightarrow - x \cdot 4 x^{2} - x \cdot - 2 x - 5 x^{3}$ $=> -x * 4 x^2 - x * -2x - 5x^3$ Removing the bracket.

$\Rightarrow - 4 (x^{2} \cdot x) + (2 x \cdot x) - 5 x^{3}$ $=> - 4 (x^2 * x) + (2 x * x) - 5x^3$

$= > - 4 x^{3} + 2 x^{2} - 5 x^{3}$ $= > -4 x^3 + 2 x^2 - 5 x^3$

$\Rightarrow - 4 x^{3} - 5 x^{3} + 2 x^{2}$ $=> -4x^3 - 5 x^3 + 2x^2$ Grouping like terms.

$\Rightarrow - x^{3} (4 + 5) + 2 x^{2}$ $=> -x^3 (4 + 5) + 2 x^2$

$\Rightarrow - 9 x^{3} + 2 x^{2}$ $=> -9x^3 + 2x^2$

How do you multiply −x(4x2−2x)−5x3-x (4x^2 - 2x) - 5x^3?