How do you perform the division $(3 y^{2} + 4 y - 32) \div (y + 4)$ $(3y^2 +4y -32) div(y +4)$ ?

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How do you perform the division $(3 y^{2} + 4 y - 32) \div (y + 4)$ $(3y^2 +4y -32) div(y +4)$ ?

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Answer 1 · 2016-10-24T12:29:52

The result of the division is $3 y - 8$ $3y-8$

Explanation:

we make a long division

$3 y^{2}$ $3y^2$ $+ 4 y$ $+4y$ $a a$ $color(white)(aa)$ $- 32$ $-32$ $∣$ $∣$ $y + 4$ $y+4$
$3 y^{2} + 12 y$ $3y^2+12y$ $a a a a$ $color(white)(aaaa)$ $∣$ $∣$ $3 y - 8$ $3y-8$
$a$ $color(white)(a)$ $0 - 8 y - 32$ $0-8y-32$
$a a a a a$ $color(white)(aaaaa)$ $8 y - 32$ $8y-32$
$a a a a a a$ $color(white)(aaaaaa)$ $0 + 0$ $0+0$

So the remainder is $0$ $0$

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How do you perform the division $(3 y^{2} + 4 y - 32) \div (y + 4)$ $(3y^2 +4y -32) div(y +4)$ ?

1 Answer

Explanation:

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How do you perform the division (3y^2 +4y -32) div(y +4)(3y2+4y−32)÷(y+4)(3y^2 +4y -32) div(y +4)?

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Explanation:

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How do you perform the division $(3 y^{2} + 4 y - 32) \div (y + 4)$ $(3y^2 +4y -32) div(y +4)$ ?