How do you perform the operation and write the result in standard form given #(3+sqrt(-5))(7-sqrt(-10))#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Shwetank Mauria May 7, 2017 #(3+sqrt(-5))(7-sqrt(-10))=(21+5sqrt2)-(3sqrt10+7sqrt5)i# Explanation: #(3+sqrt(-5))(7-sqrt(-10))# = #3×7-3×sqrt(-10)-7sqrt(-5)+sqrt(-5)sqrt(-10)# = #21-3sqrt((-1)×10)-7sqrt((-1)×5)+sqrt((-5)×(-10))# = #21-3sqrt10×sqrt(-1)-7sqrt5×sqrt(-1)+sqrt50# = #(21+sqrt50)-(3sqrt10+7sqrt5)sqrt(-1)# = #(21+5sqrt2)-(3sqrt10+7sqrt5)i# as #sqrt(-1)=i# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 1841 views around the world You can reuse this answer Creative Commons License