How do you plot $A (- 6, - \frac{π}{6})$ $A(-6,-pi/6)$ , $B (- 5, - \frac{π}{2})$ $B(-5,-pi/2)$ , and $C (- 8, - \frac{π}{4})$ $C(-8,-pi/4)$ in a polar coordinate system?

Question

8491 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-24T19:46:03

Change the radius from negative to positive by adding $π$ $pi$ to the angle.

$A (- 6, - \frac{π}{6}) \to A (6, \frac{5 π}{6})$ $A(-6,-pi/6) to A(6,(5pi)/6)$

Here is the point plotted on a polar plane:

![Desmos.com]( useruploads.socratic.org )

$B (- 5, - \frac{π}{2}) \to B (5, \frac{π}{2})$ $B(-5,-pi/2)to B(5,pi/2)$

Here is the point plotted on a polar plane:

![Desmos.com]( useruploads.socratic.org )

$C (- 8, - \frac{π}{4}) \to C (8, \frac{3 π}{4})$ $C(-8,-pi/4)toC(8,(3pi)/4)$

Here is the point plotted on a polar plane:

![Desmos.com]( useruploads.socratic.org )

How do you plot A(−6,−π6)A(-6,-pi/6), B(−5,−π2)B(-5,-pi/2), and C(−8,−π4)C(-8,-pi/4) in a polar coordinate system?