How do you plot the polar coordinate $(2, \frac{11 π}{6})$ $(2, (11pi)/6)$ ?

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How do you plot the polar coordinate $(2, \frac{11 π}{6})$ $(2, (11pi)/6)$ ?

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Answer 1 · 2018-07-05T17:11:57

The given polar coordinates $(r, θ) \equiv (2, \frac{11 π}{6})$ $(r, \theta)\equiv (2, {11\pi}/6)$ has the following Cartesian coordinates

$x = r cos θ = 2 cos (\frac{11 π}{6}) = 2 cos (\frac{π}{6}) = 2 \cdot \frac{\sqrt{3}}{2} = \sqrt{3}$ $x=r\cos\theta=2\cos({11\pi}/6)=2\cos(\pi/6)=2\cdot\sqrt3/2=\sqrt3$

$y = r sin θ = 2 sin (\frac{11 π}{6}) = - 2 sin (\frac{π}{6}) = - 2 \cdot \frac{1}{2} = - 1$ $y=r\sin\theta=2\sin({11\pi}/6)=-2\sin(\pi/6)=-2\cdot1/2=-1$

Now, take $x = \sqrt{3}$ $x=\sqrt3$ units on +ve axis & $y = 1$ $y=1$ unit on -ve y-axis to specify the location of given point

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How do you plot the polar coordinate $(2, \frac{11 π}{6})$ $(2, (11pi)/6)$ ?

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