How do you plot the polar coordinate $(- 3, \frac{23 π}{12})$ $(-3,(23pi)/12)$ ?

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How do you plot the polar coordinate $(- 3, \frac{23 π}{12})$ $(-3,(23pi)/12)$ ?

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Answer 1 · 2016-12-10T02:59:35

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Explanation:

First get The angle $\frac{23 π}{12}$ $(23pi)/12$ which would lie in $I V^{t h}$ $IV^(th)$ quadrant and then measure distance of 3 in the opposite direction to get the desired point, as shown below:

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How do you plot the polar coordinate $(- 3, \frac{23 π}{12})$ $(-3,(23pi)/12)$ ?

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Explanation:

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How do you plot the polar coordinate (−3,23π12)(-3,(23pi)/12)?

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How do you plot the polar coordinate $(- 3, \frac{23 π}{12})$ $(-3,(23pi)/12)$ ?