How do you plot the polar coordinate $(- 3, \frac{- π}{3})$ $(-3, (-pi)/3)$ ?

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How do you plot the polar coordinate $(- 3, \frac{- π}{3})$ $(-3, (-pi)/3)$ ?

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Answer 1 · 2016-11-30T22:49:58

see below

Explanation:

From the polar axis (positive x-axis) go down $60^{\circ}$ $60^@$ or $\frac{π}{3}$ $pi/3$ . You will end up on the ray $300^{\circ}$ $300^@$ or $\frac{5 π}{3}$ $(5pi)/3$ .

The -3 means that you are going to plot the point on the opposite ray to $\frac{5 π}{3}$ $(5pi)/3$ which is $\frac{2 π}{3}$ $(2pi)/3$ . So plot the point on the 3rd circle and the ray $\frac{2 π}{3}$ $(2pi)/3$ .

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How do you plot the polar coordinate $(- 3, \frac{- π}{3})$ $(-3, (-pi)/3)$ ?

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How do you plot the polar coordinate $(- 3, \frac{- π}{3})$ $(-3, (-pi)/3)$ ?