How do you prove # (1-sec^2x) / (secx - 1) = secx + 1 #?
1 Answer
Mar 20, 2016
This is not a valid identity.
Explanation:
We can show this is an invalid identity by plugging in
#(1-sec^2(pi/3))/(sec(pi/3)-1)!=sec(pi/3)+1#
#(1-2^2)/(2-1)!=2+1#
#(-3)/1!=3#
#-3!=3#
