How do you prove $tantheta - cot^2theta+cottheta= sin^2theta- cos^2theta$ ?

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Answer 1 · 2018-03-13T06:53:11

Please check the Problem.

The Assertion doesn't seem to be true, as can be seen from

the following :

$"For "theta=pi/4," the L.H.S.="1-1^2+1=1," whereas, "$

$"the R.H.S.="(1/sqrt2)^2-(1/sqrt2)^2=0$ .

How do you prove tantheta - cot^2theta+cottheta= sin^2theta- cos^2theta tantheta - cot^2theta+cottheta= sin^2theta- cos^2theta?