How do you rationalize the numerator for #sqrt(cosx/sinx)#?
1 Answer
Feb 25, 2017
Explanation:
We can rewrite the entire expression as
#sqrt(cosx)/sqrt(sinx)#
We multiply both numerator and denominator by the numerator to rationalize.
#sqrt(cosx)/sqrt(sinx) * sqrt(cosx)/sqrt(cosx)#
#cosx/sqrt(sinxcosx)#
Add an absolute value on the
#|cosx|/sqrt(sinxcosx)#
Hopefully this helps!