How do you reduce #-8 + b^2# by #5 + b^2#?

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Answer 1 · 2018-05-04T08:14:35

By subtracting #-13#

How do you reduce #20# by #8#,

of course by #color(red)"subtracting "12#, which means #20-8# i.e. subtract latter number #8# from former number #20#

Hence to reduce #-8+b^2# by #5+b^2#,

we should subtract latter number #5+b^2# from former number #-8+b^2# i.e.

#-8+b^2-(5+b^2)#

= #-8+b^2-5-b^2#

= #-13#

i.e. by subtracting #-13#