How do you rewrite the following quadratic equation in vertex form: y=x^2-8x+13y=x28x+13?

1 Answer
Mar 20, 2017

minimum vertex with value- 33 at (4, -3)(4,3)

Explanation:

y = x^2 - 8 x + 13y=x28x+13

Consider coefficient of xx, divide by 2 and make a parentesis and ssquare them. since infront of parentesis is +ve value, then deduct the squared number in parentesis in the equation to balance it.
y = (x - 4)^2 - (-4)^2 + 13y=(x4)2(4)2+13
y = (x - 4)^2 - 16 + 13y=(x4)216+13
y = (x - 4)^2 - 3y=(x4)23

since infront of (x-4)^2(x4)2 is +ve sign, it is a minimum vertex with value- 33 at (4, -3)(4,3)