Question

How do you rewrite the following quadratic equation in vertex form: `y=x^2-8x+13`?

Answer 1

minimum vertex with value`- 3` at `(4, -3)`

Explanation:

`y = x^2 - 8 x + 13`

Consider coefficient of `x`, divide by 2 and make a parentesis and ssquare them. since infront of parentesis is +ve value, then deduct the squared number in parentesis in the equation to balance it.
`y = (x - 4)^2 - (-4)^2 + 13`
`y = (x - 4)^2 - 16 + 13`
`y = (x - 4)^2 - 3`

since infront of `(x-4)^2` is +ve sign, it is a minimum vertex with value`- 3` at `(4, -3)`