How do you simplify $1/6(3x+5y)+2/3(3/5x-6y)$ ?

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Answer 1 · 2017-03-25T15:03:49

$= (9x)/10 - 3 1/6y$

Note that there are twp terms, each has brackets which can be removed by using the distributive law.

$1/6(3x+5y) +2/3(3/5x-6y)$

Here are the details of the multiplication and cancelling.

$=(1xxcancel3x)/cancel6_2 + (1xx5x)/6 + (2xxcancel3x)/(cancel3xx5) -(2xxcancel6^2y)/cancel3$

$=1/2x+5/6y +2/5x-4y$

$=(1/2x+2/5x)+(5/6y -4y)" "larr$ collect like terms

$=(5x+4x)/10 -3 1/6y" "larr$ fraction rules, LCD

$= (9x)/10 - 3 1/6y$

How do you simplify 1/6(3x+5y)+2/3(3/5x-6y)1/6(3x+5y)+2/3(3/5x-6y)?