How do you simplify 1/6(3x+5y)+2/3(3/5x-6y)16(3x+5y)+23(35x6y)?

1 Answer
Mar 25, 2017

= (9x)/10 - 3 1/6y=9x10316y

Explanation:

Note that there are twp terms, each has brackets which can be removed by using the distributive law.

1/6(3x+5y) +2/3(3/5x-6y)16(3x+5y)+23(35x6y)

Here are the details of the multiplication and cancelling.

=(1xxcancel3x)/cancel6_2 + (1xx5x)/6 + (2xxcancel3x)/(cancel3xx5) -(2xxcancel6^2y)/cancel3

=1/2x+5/6y +2/5x-4y

=(1/2x+2/5x)+(5/6y -4y)" "larr collect like terms

=(5x+4x)/10 -3 1/6y" "larr fraction rules, LCD

= (9x)/10 - 3 1/6y