How do you simplify $\frac{1 - {cos}^{2} x}{sin x}$ $(1-cos^2x)/sinx$ ?

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Answer 1 · 2015-11-15T23:09:28

Use ${cos}^{2} x + {sin}^{2} x = 1$ $cos^2 x + sin^2 x = 1$ to find:

$\frac{1 - {cos}^{2} x}{sin x} = sin x$ $(1-cos^2 x)/(sin x) = sin x$

Since ${cos}^{2} x + {sin}^{2} x = 1$ $cos^2 x + sin^2 x = 1$ , we find:

$\frac{1 - {cos}^{2} x}{sin x} = \frac{{sin}^{2} x}{sin x} = sin x$ $(1-cos^2 x)/(sin x) = (sin^2 x)/(sin x) = sin x$

How do you simplify 1−cos2xsinx(1-cos^2x)/sinx?