How do you simplify #[(1 + sin u) / cos u] + [(cos u) / 1 + sin u]#?

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Answer 1 · 2015-10-24T16:45:17

Take the LCM

There are many ways of doing it

Here's an example:

#((1+sinu)+cosu(cosu)+cosu(sinu))/cosu#

#(1+sinu+cos^2u+sinucosu)/cosu#

#(1+sinu+(1-sin^2u)+sinucosu)/cosu#

#2/cosu+(sinu-sin^2u)/cosu+(sinucosu)/cosu#

#2secu+sinu/cosu(1-sinu)+sinu#

#2secu+tanu(1-sinu)+sinu#