How do you simplify #(-10)+(+8)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Daniel L. Nov 21, 2016 #(-10)+8=-2# Explanation: You can see it on a number line: number #(-10)# is #10# units left from zero. Adding #8# means moving #8# units right, so you end at #2# units left from zero (i.e. at #(-2)#) Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 4226 views around the world You can reuse this answer Creative Commons License