How do you simplify (15y-15)/(3y^2+9y-12)15y−153y2+9y−12?

1 Answer
Deepak G.
Aug 6, 2016

=5/(y+4)=5y+4

Explanation:

(15y-15)/(3y^2+9y-12)15y−153y2+9y−12
=15(y-1)/(3(y^2+3y-4))=15y−13(y2+3y−4)
=5(y-1)/(y^2+3y-4=5y−1y2+3y−4
=5(y-1)/(y^2+4y-y-4)=5y−1y2+4y−y−4
=5(y-1)/(y(y+4)-1(y+4)=5y−1y(y+4)−1(y+4)
=5(y-1)/((y+4)(y-1))=5y−1(y+4)(y−1)
=5cancel(y-1)/((y+4)cancel(y-1))
=5/(y+4)

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