How do you simplify $\frac{17 k + 14}{9} - \frac{12 k + 1}{9}$ $(17k+14)/9-(12k+1)/9$ ?

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How do you simplify $\frac{17 k + 14}{9} - \frac{12 k + 1}{9}$ $(17k+14)/9-(12k+1)/9$ ?

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Answer 1 · 2018-05-10T21:31:09

$\frac{5 k + 13}{9}$ $[5k+13]/9$

Explanation:

The fraction have the same denominators so just subtract the numerators. E.g. $\frac{5}{9} - \frac{4}{9} = \frac{5 - 4}{9} = \frac{1}{9}$ $5/9-4/9=(5-4)/9=1/9$

$\frac{17 k + 14}{9} - \frac{12 k + 1}{9} = \frac{17 k + 14 - 12 k - 1}{9} = \frac{5 k + 13}{9}$ $(17k+14)/9-(12k+1)/9=[17k+14-12k-1]/9=[5k+13]/9$

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How do you simplify $\frac{17 k + 14}{9} - \frac{12 k + 1}{9}$ $(17k+14)/9-(12k+1)/9$ ?

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How do you simplify $\frac{17 k + 14}{9} - \frac{12 k + 1}{9}$ $(17k+14)/9-(12k+1)/9$ ?