Question

How do you simplify `(2-2i)^2`?

Answer 1

`z=0-8i`

Explanation:

Let ,

`z=(2-2i)^2 ,where ,z inCC`

`:.z=4-8i+4i^2`

`:.z=4-8i+4(-1)to[because i^2=-1]`

`:.z=4-8i-4`

`:.z=0-8i`