How do you simplify #(-2-2i)(-4-3i)(7+8i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Binayaka C. May 24, 2017 # -98 +114 i # Explanation: #i^2=-1# # (2-2i) * (-4-3i) *(7+8i) =# # { (2-2i) (-4-3i) } * (7+8i) =# # (2+14i) (7+8i) = -98 +114 i # [Ans] Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 5454 views around the world You can reuse this answer Creative Commons License