How do you simplify $\frac{2}{3} (9 b - 27)$ $2/3 (9b - 27)$ ?

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Answer 1 · 2015-07-08T08:28:11

$= 6 b - 18$ $=color(blue)(6b-18)$

$9 b - 27$ $9b-27$ has 9 in common to both terms

$9 b - 27 = 9 (b - 3)$ $9b-27=color(blue)(9(b-3)$

Rewriting the expression:
$\frac{2}{3} (9 b - 27) = \frac{18}{3} (b - 3)$ $2/3(9b-27) = 18/3(b-3)$

$= 6 (b - 3)$ $=6(b-3)$

$= 6 b - 18$ $=color(blue)(6b-18)$

How do you simplify 23(9b−27)2/3 (9b - 27)?