How do you simplify #-2/(3-i)#?
1 Answer
Apr 25, 2018
Explanation:
#"to simplify the fraction multiply the numerator and "#
#"denominator by the "color(blue)"conjugate ""of the"#
#"denominator"#
#"the conjugate of "3-i" is "3color(red)(+)i#
#rArr-(2(3+i))/((3-i)(3+i))toi^2=-1#
#=(-6-2i)/(9+1)=(-6-2i)/10=-3/5-1/5i#
