How do you simplify $\frac{2}{5 m} - \frac{1}{15 m^{3}}$ $2/(5m)-1/(15m^3)$ ?

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Answer 1 · 2018-03-12T19:56:54

$\frac{6 m^{2} - 1}{15 m^{3}}$ $(6m^2 - 1)/(15m^3)$

$\frac{2}{5 m} - \frac{1}{15 m^{3}}$ $2/(5m) - 1/(15m^3)$

We need a common denominator:

$\frac{3 m^{2}}{3 m^{2}} \times \frac{2}{5 m} - \frac{1}{15 m^{3}}$ $(3m^2)/(3m^2) xx (2)/(5m) - (1)/(15m^3)$

$\frac{6 m^{2}}{15 m^{3}} - \frac{1}{15 m^{3}}$ $(6m^2)/(15m^3) - (1)/(15m^3)$

$\frac{6 m^{2} - 1}{15 m^{3}}$ $(6m^2 - 1)/(15m^3)$

Answer 2 · 2018-03-12T19:57:04

$\frac{6 m^{2} - 1}{15 m^{3}}$ $(6m^2-1)/(15m^3)$

Expand the fraction

$\frac{3 m^{2} \cdot 2}{3 m^{2} \cdot 5 m} - \frac{1}{15 m^{3}}$ $(3m^2*2)/(3m^2*5m)-1/(15m^3)$

Calculate the products

$\frac{6 m^{2}}{15 m^{3}} - \frac{1}{15 m^{3}}$ $(6m^2)/(15m^3)-1/(15m^3)$

Write all the numerators above the common denominator

$\frac{6 m^{2} - 1}{15 m^{3}}$ $(6m^2-1)/(15m^3)$

How do you simplify 25m−115m32/(5m)-1/(15m^3)?