How do you simplify #(-2-i)(4+i)#?

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Answer 1 · 2016-10-02T02:26:28

#-7-6i#

#(-2-i)(4+i)#

Distribute by multiplying each term in the first binomial by each term in the second binomial (i.e. FOIL).

#(-2*4)+(-2*i)+(-i*4)+(-i*i)#

#-8-2i-4i-i^2color(white)(aaa)# Combine like terms

#-8-6i-i^2color(white)(aaa)# Recall that #i^2=-1#

#-8-6i-(-1)#

#-8-6i+1#

#-7-6i#