How do you simplify #20 / (3+i)#?
1 Answer
Dec 16, 2015
Multiply both numerator and denominator by the Complex conjugate
#20/(3+i) = 6-2i#
Explanation:
#20/(3+i)#
#= (20(3-i))/((3+i)(3-i))#
#= (20(3-i))/(3^2+1)#
#= (20(3-i))/10#
#=6-2i#
