Question

How do you simplify `(2c^2+2c-12)/(-8+2c+c^2)`?

Answer 1

`(2(c+3))/(c+4)`

Explanation:

`(2c^2+2c-12)/(-8+2c+c^2)`

=`(2(c^2+c-6))/(c^2 +2c-8)" " (larr"common factor of 2")/(larr"re-arrange the terms")`

`=(2(c+3)cancel((c-2)))/((c+4)cancel((c-2))) " "larr` find factors of quadratics

`=(2(c+3))/(c+4)`