How do you simplify #2i+4(4-2i)#?

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Answer 1 · 2016-09-04T14:35:29

#16-6i#

To simplify #color(blue)"distribute the bracket and collect like terms"#

#2i+16-8i=16-6i#

#rArr2i+4(4-2i)=16-6i#

Answer 2 · 2016-09-04T14:37:51

#16 - 6 i#

We have: #2 i + 4 (4 - 2 i)#

Let's expand the parentheses:

#= 2 i + 16 - 8 i#

Combine the imaginary terms to get:

#= 16 - 6 i#