How do you simplify $2i+4(4-2i)$ ?

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Answer 1 · 2016-09-04T14:35:29

$16-6i$

To simplify $color(blue)"distribute the bracket and collect like terms"$

$2i+16-8i=16-6i$

$rArr2i+4(4-2i)=16-6i$

Answer 2 · 2016-09-04T14:37:51

$16 - 6 i$

We have: $2 i + 4 (4 - 2 i)$

Let's expand the parentheses:

$= 2 i + 16 - 8 i$

Combine the imaginary terms to get:

$= 16 - 6 i$

How do you simplify 2i+4(4-2i)2i+4(4-2i)?