How do you simplify $(2k)/8 + (3k)/6$ ?

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Answer 1 · 2016-06-04T21:32:59

Start simplifying the number in front of $k$ with the denominator

$(2k)/8=(2k)/(2*4)=k/4$

$(3k)/6=(3k)/(2*3)=k/2$

Now we have

$(2k)/8+(3k)/6=k/4+k/2$

We use as common denominator $4$ .

$k/4+k/2=k/4+(2k)/4$

$=(k+2k)/4$

$=(3k)/4$ .

You cannot simplify more because 3 and 4 do not share any factor.

How do you simplify (2k)/8 + (3k)/6(2k)/8 + (3k)/6?