How do you simplify #(2k)/8 + (3k)/6#?

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Answer 1 · 2016-06-04T21:32:59

Start simplifying the number in front of #k# with the denominator

#(2k)/8=(2k)/(2*4)=k/4#

#(3k)/6=(3k)/(2*3)=k/2#

Now we have

#(2k)/8+(3k)/6=k/4+k/2#

We use as common denominator #4#.

#k/4+k/2=k/4+(2k)/4#

#=(k+2k)/4#

#=(3k)/4#.

You cannot simplify more because 3 and 4 do not share any factor.